线段树模板题

题目:POJ 3468

代码:

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
#include<iostream>

using namespace std;

const int maxN = 101111;

int N, Q;
int a[maxN];

class TreeNode {
public:
int l, r;
long long tag, sum;
TreeNode *lch, *rch;

TreeNode(int l, int r): l(l), r(r) {
tag = sum = 0;
lch = rch = NULL;
}

void Add(long long x) {
tag += x;
sum += x * (r - l + 1);
}

void PushDown() {
if (tag != 0) {
lch->Add(tag);
rch->Add(tag);
tag = 0;
}
}

void Update() {
sum = lch->sum + rch->sum;
}
};

TreeNode* BuildTree(int* a, int l, int r) {
TreeNode* v = new TreeNode(l, r);
if (l == r) {
v->sum = a[l];
return v;
}
int mid = (l + r) / 2;
v->lch = BuildTree(a, l, mid);
v->rch = BuildTree(a, mid + 1, r);
v->Update();
return v;
}

void Add(TreeNode* v, int l, int r, int x) {
if (l <= v->l && v->r <= r) {
v->Add(x);
return;
}
v->PushDown();
int mid = (v->l + v->r) / 2;
if (l <= mid) Add(v->lch, l, r, x);
if (r > mid) Add(v->rch, l, r, x);
v->Update();
}

long long GetSum(TreeNode* v, int l, int r) {
if (l <= v->l && v->r <= r) return v->sum;
v->PushDown();
int mid = (v->l + v->r) / 2;
long long res = 0;
if (l <= mid) res += GetSum(v->lch, l, r);
if (r > mid) res += GetSum(v->rch, l, r);
return res;
}

void Work() {
cin >> N >> Q;
for (int i = 0; i < N; i++) scanf("%d", &a[i]);
TreeNode* root = BuildTree(a, 0, N - 1);
for (int i = 0; i < Q; i++) {
char op = 0;
while (op != 'C' && op != 'Q') op = getchar();
int l, r, x;
scanf("%d %d", &l, &r);
l--, r--;
if (op == 'C') {
scanf("%d", &x);
Add(root, l, r, x);
}
else if (op == 'Q') {
printf("%lld\n", GetSum(root, l, r));
}
else throw "Invalid operation.";
}
}

int main() {
Work();
return 0;
}